Class Description

VPk: Valiant P Over Field k

The class of efficiently-solvable problems in Valiant's algebraic complexity theory.

More formally, the input consists of constants c1,...,cm and indeterminates X1,...,Xn over a base field k (for instance, the complex numbers or Z2). The desired output is a collection of polynomials over the Xi's. The complexity is the minimum number of pairwise additions, subtractions, and multiplications needed by a straight-line program to produce these polynomials. VPk is the class of problems whose complexity is polynomial in n. (Hence, VPk is a nonuniform class, in contrast to PC and PR.)

Originated in [Val79b]; see [Bur00] for more information.

Contained in VNPk and VQPk, and contains VNCk.

Linked From

PC: Polynomial-Time Over The Complex Numbers

An analog of P for Turing machines over a complex number field.

Defined in [BCS+97].

See also PR, NPC, NPR, VPk.

More about...


PR: Polynomial-Time Over The Reals

An analog of P for Turing machines over a real number field.

Defined in [BCS+97].

See also PC, NPC, NPR, VPk.

More about...


VNCk: Valiant NC Over Field k

Has the same relation to VPk as NC does to P.

More formally, the class of VPk problems computable by a straight-line program of depth polylogarithmic in n.

Surprisingly, VNCk = VPk for any k [VSB+83].

More about...


VNPk: Valiant NP Over Field k

A superclass of VPk in Valiant's algebraic complexity theory, but not quite the analogue of NP.

A problem is in VNPk if there exists a polynomial p with the following properties:

Originated in [Val79b].

If the field k has characteristic greater than 2, then the permanent of an n-by-n matrix of indeterminates is VNPk-complete under a type of reduction called p-projections ([Val79b]; see also [Bur00]).

A central conjecture is that for all k, VPk is not equal to VNPk. Bürgisser [Bur00] shows that if this were false then:

In both cases, PH collapses to Σ2P.

More about...


VQPk: Valiant QP Over Field k

Has the same relation to VPk as QP does to P.

Originated in [Val79b].

The determinant of an n-by-n matrix of indeterminates is VQPk-complete under a type of reduction called qp-projections (see [Bur00] for example). It is an open problem whether the determinant is VPk-complete.

More about...